Solve 2x² - 2√6x + 3 =0 by quadratic formula
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2
Answer:
Hence they have real and equal roots......
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Answered by
0
Answer:
HERE,
a= 2, b= -2√6 & c= 3
Now,
D= b²-4ac
= (-2√6)²- 4(2)(3)
= 24-24
= 0 > 0
THEREFORE,
IT'S A REAL ROOT & EQUAL
THEN,
X= -b / 2a
= -(- 2√6)/2(2)
= 2√6/4. ( CUT DOWN 4 BY 2, THEN IT WILL....)
= √6/2
= √2×3/2
= √2×3/ √2×√2
= √3/√2
HENCE,
THE ROOT IS √3/√2
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