Solve: 2x²- 2√ x + 1=0.
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2x² - 2√2x + 1 = 0
2x² - √2x - √2x + 1 = 0
√2x ( √2x - 1 ) - 1 ( √2x - 1 ) = 0
( √2x - 1 ) ( √2x - 1 ) = 0
* ( √2x - 1 ) = 0
x = 1/√2
* ( √2x - 1 ) = 0
x = 1/√2
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