Question

solve 2x²-5x+3=0 by the method of completing the squares​

Answer 1

Answer:

solve 2x²-5x+3=0 by the method of completing the squares

Answer 2

SOLUTION:-

Given that:-

$2 {x}^{2} - 5x + 3 = 0$

By mid-term splitting ,

${2x}^{2} - 2x - 3x + 3 = 0$

$(x - 1)(2x - 3) = 0$

$2x(x - 1) - 3(x - 1) = 0$

$(x - 1)(2x - 3) = 0$

$x - 1 = 0 \: or \: 2x - 3 = 0$

$x = 1 \: \: or \: \: 2x = 3$

$x = 1 \: \: or \: \: \: x = \frac{3}{2}$

Hope it will help you!!!