Solve 2x2-6x+3=0by completing square
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Answer:
2x^2-6x+3=0...
Step-by-step explanation:
2x^2-6x=-3
x^2-3x=-3/2...{Divide Both Side by 2}
x^2-3x+(-3/2)^2=-3/2+(3/2)^2...{Add(3/2)^2 Both Side}
(x-3/2)^2=3/4
[x1=-√3+3/2] ;;;; [x2=√3+3/2]
Mark as BRAINLIST.......
Thanks....
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