Question

Solve √2x²+ 7x +5√2 = 0 by quadratic formula

Answer 1

Answer:

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ = > x = \frac{ - 7 \pm \sqrt{ {7}^{2} - 4 \times \sqrt{2} \times 5 \sqrt{2} } }{2 \times \sqrt{2} } \\ = > x = \frac{ - 7 \pm \sqrt{49 - 40} }{2 \sqrt{2} } \\ = > x = \frac{ - 7 \pm \sqrt{ 9 } }{2 \sqrt{2} } \\ = > x = \frac{ - 7 \pm3}{2 \sqrt{2} } \\ = > x = \frac{ - 7 + 3}{2 \sqrt{2} } \: or \: \frac{ - 7 - 3}{2 \sqrt{2} } \\ = > x = \frac{ - 4}{2 \sqrt{2} } \: or \: \: \frac{ - 10}{2 \sqrt{2} } \\ = > x = - \sqrt{2} \: or \: \frac{5 \sqrt{2} }{2}$

Answer 2

Answer:

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0 \\ \sqrt{2}x(x + \sqrt{2} ) + 5(x + \sqrt{2}) = 0 \\ \sqrt{2}x + 5)(x + \sqrt{2}) = 0 \\ x = \frac{ - 5}{ \sqrt{2} } \: or - \sqrt{2} \: is \: the \: answer$

note- √2×5√2=5×2=10

7+2=10 this is by factorization method