Question

Solve √2x²+ 7x +5√2 = 0, by using quadratic formula

Answer 1

Answer:

$- 5 \div \sqrt{2} \: and \: - \sqrt{2}$

Step-by-step explanation:

b=7

a=√2

c=5√2

$( - b + - \sqrt{{b}^{2} - 4ac}) \div 2a$

= -7±(√7×7- 4×√2×5√2)/2√2

=-7±3/2√2

Answer 2

-b+- root [b^2-4ac]/2a = -7 +-(7)^2 - 4(root2)(5 root2)/ 2×root 2

[ +-(plus or minus)]

= -7+- root [49 - 4×10]/ 2 root 2 ( root 2 × 5 root 2 = 10)

= -7 +- root [9]/ 2 root 2

= -7+- 3/2 root 2 ( root 9 =3)

then values are 1. -7+3/2 root 2

2. -7-3/2 root 2.

I hope this will help you. . . . .