Question

Solve 2xsquare_7x+3=0 by quadratic formula

Answer 1

Answer:

given equation = 2x^2 -7x+3=0

here, a=2 b=-7 and c=3

Quadratic formmula =

-b ±√(b^2 - 4ac)/ 2a

now, b^2-4ac = (-7)^2-4×2×3

= 49-24 = 25

so according to the formula,

x= -(-7)±√25 = 7±5

2×2 4

so x = 7+5 or 7-5

4 4

=> x= 12/4 = 3 or 2/4= 1/2

hope it will help you

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