Question

Solve (2xy + y - tan y)dx +(x-x tan y+sec y)dy =0

Answer 1

Answer:

The answer to your question is........0

Answer 2

Answer:

may be there's not a ' + ' Sign between tan and sec . Recheck question

$(2xy + y - \tan(y) )dx + (x - x \tan(y) \sec(y) )dy = 0 \\ \\ (2x + y)dx + xdy = ( \tan(y) dx + x \tan(y) \sec(y) dy) \\ \\ 2xdx + d(xy) = d(x \tan(y) ) \\ \\ integrate \\ \\ {x}^{2} + xy = x \tan(y) + c$