solve (2xy-y²-y)dx+(2xy-x²-x)dy=0
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1
Answer:
answer is 12
Step-by-step explanation:
becauseGiven, d(x
2
y)=d(xy)+d(xy
2
)
⇒x
2
y=xy+xy
2
+c
At x=1,y=1 ⇒ c = -1
⇒x
2
y=xy+xy
2
−1⇒y=−y+y
2
−1
∴y
2
+2y+1=0⇒y=−1
∴12y∣y(−1)∣=12
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