solve 2y-1/2+y=4y-3/3+2y
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Answered by
2
Answer:
Step-by-step explanation:
2y+1/2+y = 4y-3/3+2y
(2y+1)(3+2y) = (4y-3)(2+y)
2y(3+2y)+1(3+2y) = 2(4y-3)+y(4y-3)
6y+4y²+3+2y = 8y-6+4y²-3y
4y² got cancelled
6y+2y-8y+3y = -6-3
3y = -9
Y=-3
Hope it helps
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somay882:
thanks so much
Answered by
1
Step-by-step explanation:
2y+1/2+y = 4y-3/3+2y
(2y+1)(3+2y) = (4y-3)(2+y)
2y(3+2y)+1(3+2y) = 2(4y-3)+y(4y-3)
6y+4y²+3+2y = 8y-6+4y²-3y
4y² got cancelled
6y+2y-8y+3y = -6-3
3y = -9
Y=-3
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