Math, asked by ParthBerad, 1 year ago

solve 2y^2+9y+10=0 by complete ing square method?

Answers

Answered by Anonymous
92
Heya frnd.!!!

Here's your answer...

⭐ QUADRATIC EQUATIONS ⭐

2y² + 9y + 10 = 0

=> 2 ( y² + 9/2y + 5) = 0

=> y² + 9/2y + 5 = 0

=> y² + 9/2y = -5

=> y² + 9/2y + 81/¹6 = -5 + 81/4

=> (y + 9/4)² = 1/16

=> (y + 9/4) = ± 1/4

=> (y + 9/4) = 1/4 or (y + 9/4) = -1/4

=> y = -8/4 or y = -10/4

=> y = -2 or y = -5/2


Hope this would help you!!!
Answered by BendingReality
22

Answer:

- 2  OR  - 5 / 2

Step-by-step explanation:

Given :

p ( y ) = 2 y² + 9 y +  10 = 0

Dividing by coefficient of y² :

⇒ 2 / 2 y² + 9 / 2 y + 10 / 2 = 0 / 2

⇒ y² + 9 / 2 y + 5 = 0

Now transfer 5 [ constant term ] R.H.S. side :

⇒ y² + 9 / 2 y = -  5

Now Adding ( 1 / 2 × coefficient of y )²

i.e. ( 9 / 4 )² = 81 / 16

⇒ y² + 9 / 2 y + 81 / 16 = 81 / 16 -  5

⇒ y² + 2 . 9 / 4 y + ( 9 / 4 )² = 1 / 16

⇒ ( y + 9 / 4 )² = ( 1 / 16 )

⇒ ( y + 9 / 4 ) = ± ( 1 / 4 )

Value of y as :

y + 9 / 4 = 1 / 4

y = 1 / 4 - 9 / 4

y = - 8 / 4

y = - 2

OR

y + 9 / 4 = - 1 / 4

y = - 9 / 4 - 1 / 4

y = - 10 / 4

y = - 5 / 2 .

Therefore , the value of y is ' - 2 '  OR  ' - 5 / 2 ' .

Similar questions