solve. 2y+5/2=26/3-y
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Step-by-step explanation:
we have 2y + 5/2 = 26/ 3 - y
2y + 5 * ( 3 - y) = 2 * 26
6y - 2y^2 + 15 - 5y = 52
y - 2y^2 + 15 = 52
y - 2y^2 + 15 - 52 = 0
y - 2y^2 -37 = 0
2y^2 - y + 37 = 0
here a = 2
b = -1
c = 37
now find solution bt formula
roots = - b +- sqrt( b - 4ac) / 2a
you can find 2 solutions of y , the one which satisfy the condition is the required solution
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