Math, asked by chithararbatt, 1 year ago

Solve 2y/y-4 + 2y-5/y-3 = 25/3

Answers

Answered by abhi178
0
2y/(y-4)+(2y-5)/(y-3)=25/3

=> 2y (y-3)+(2y-5)(y-4)=25/3 (y-4)(y-3)

=> 2y^2-6y+2y^2-8y-5y+20=25/3 {y^2-7y+12}

=> 13y^2-118y+240=0

y={118+_root {118^2-4 (240)(13)}/26
Similar questions