solve (2y+z) (2z-3y) using identity
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ANSWER == -6y² + yz + 2z²
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Given -- ( 2y + z ) ( 2z - 3y )
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Identity -- (a + b)² = a² + b² + 2ab
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Solution -- By Rearranging,
➟ ( 2y + z ) ( -3y + 2z )
➟ 2y ( -3y + 2z ) + z ( -3y + 2z )
➟ -6y² + 4yz -3yz + 2z²
➟ -6y² + 1yz + 2z²
➟ -6y² + yz + 2z²
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