Question

solve 2y²-3y-2=0 by prime Factorization​

Answer 1

Answer:

(y-2)(2y+1)

Step-by-step explanation:

2y²-3y-2=0

Since 2*2=4, we need to find two numbers which when added gives 3 and when multiplied, yields 4. Hence,

2y²-3y-2=0

= 2y²-4y+y-2=0

= 2y(y-2)+1(y-2)

= (y-2)(2y+1)