Question

Solve 2y² - 5y + 3 = 0 using quadratic formula​

Answer 1

Answer:

y₁ = 1.5

y₂ = 1

Step-by-step explanation:

Solve for y by using the quadratic formula:

$y_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

From the equation 2y² - 5y + 3 = 0

a = 2, b = -5, c (constant) = 3

Insert those numbers according to the quadratic formula:

$y_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4* \:2* \:3}}{2* \:2} =\\\\y_{1,\:2}=\frac{-\left(-5\right)\pm \:1}{2* \:2} =\\\\y_{1,\:2}=\frac{5\pm1}{4}$

Find y₁ by adding 5 with 1 in the numerator (+)

$y_{1}=\frac{5+1}{4}\\\\y_{1}=\frac{6}{4}\\\\y_{1}=\frac{3}{2}$

y₁ = 1.5 ✅

Find y₂ by subtracting 5 with 1 in the numerator (-)

$y_{2}=\frac{5-1}{4}\\\\y_{2}=\frac{4}{4}$

y₂ = 1 ✅

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