Question

solve
2y²+y-2=0
help me please​

Answer 1

Step-by-step explanation:

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Here is your answer!

______________________________

QUADRATIC EQUATION :

2y²-y+2=0

Comparing it with ax²+bx+c=0

We get,

a=2, b= -1 and c=2

Now, we know that

\begin{gathered}discriminant \: (d) = {b}^{2} - 4ac \\ \\ d = { (- 1)}^{2} - 4 \times 2 \times 2 \\ \\ d = 1 - 16 \\ \\ d = - 15\end{gathered}

discriminant(d)=b

2

−4ac

d=(−1)

2

−4×2×2

d=1−16

d=−15