Solve:-(3.07)^2+(0.0193)^2/(0.307)^2+(0.00193)^2
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Given (3.07)^2+(0.0193)^2/(0.307)^2+(0.00193)^2 can be written as
= 9.4249 + 0.00037249/0.094249 + 0.0000037249
= 9.42527249/0.0942527249
= 100.
Hope this helps! :)
= 9.4249 + 0.00037249/0.094249 + 0.0000037249
= 9.42527249/0.0942527249
= 100.
Hope this helps! :)
L12345:
Your answer is correct but now I have got the trick,If we remove the decimals In numerator there wil be 8 zeroes and in denominator there will be 6 zeroes.Therwfore answer will be 100
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