.Solve: 3( − 1) + 2(2 + 3) = 7
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Answered by
3
Answer:
Let
2x+3y
1
=u and
3x−2y
1
=v. Then, the given system of equations becomes
2
1
u+
7
12
v=
2
1
⇒7u+24v=7 ..(i)
and, 7u+4v=2 .(ii)
Substracting equation (ii) from equation (i), we get
20v=5⇒v=
4
1
Putting v=
4
1
in equation (i), we get
7u+6=7⇒u=
7
1
Now, u=
7
1
⇒
2x+3y
1
=
7
1
⇒2x+3y=7 (iii)
and, u=
4
1
⇒
3x−2y
1
=
4
1
⇒3x−2y=4 .(iv)
Multiplying equation (iii) by 2 and equation (iv) by 3, we get
4x+6y=14 .(v)
9x−6y=12 .(vi)
Adding equations (v) and (vi), we get
13x=26⇒x=2
Putting x=2 in equation(v), we get
8+6y=14⇒y=1
Hence, x=2,y=1 is the solution of the given system of equations.
Answered by
1
Answer:
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