solve (3+√2)(2-√3) answer fast this question
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(a-b)(a+b)=a²-b²
The above expression completely fits in this equation:
let’s substitute 2 with a: 2=a and √3 with b: √3=b
This will equate to 2²-(√3)²
The square exponent of (√3)² will cancel the under root and make it 3
Squaring 2 will give you 4
Now 4–3=1
I hope my response clearly answered your question
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Step-by-step explanation:
Let p = √(2+√3) + √(2-√3) , squaring both side
p ^2 = ( 2+ √3) + (2- √3) +2 √{(2+√3)(2- √3)}
or, p^2 = 4+2*√(4 -3)
Or, p^2 = 4 + 2*1= 6
or , p = ±√6
So, √(2+√3) + √(2-√3) = ±√6 = +√6 ( ignoring negative value )
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