Math, asked by neerusethi638, 1 year ago

Solve
3√2/√3+√6-4√3/√6+√2+√6/√2+√3

Answers

Answered by Vamikabahety
1
2√6 - 1 -√2 - 2√3 is the answer of the question by doing rationalize you can do it on

neerusethi638: Sorry but I also want the explaination that how u find out the answer
Answered by bhawnasharmad3
1

Step-by-step explanation:

Solution:

Rationalizing of all terms see in attachment.

Now, Get back to the question,

\begin{gathered}(2 \sqrt{3} + \sqrt{6} ) + (3 \sqrt{2} - 2 \sqrt{3} ) - (3 \sqrt{2} + \sqrt{6} ) \\ \\ = 2 \sqrt{3} + \sqrt{6} + 3 \sqrt{2} - 2 \sqrt{3} - 3 \sqrt{2} - \sqrt{6} \\ \\ = \cancel{2 \sqrt{3} } + \cancel{\sqrt{6} } + \cancel{3 \sqrt{2} } - \cancel{2 \sqrt{3} } - \cancel{3 \sqrt{2} } - \cancel{\sqrt{6}} \\ \\ = 0\end{gathered}(23+6)+(32−23)−(32+6)=23+6+32−23−32−6=23+6+32−23−32−6=0

Therefore, The required answer is 0.

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