solve : 3×+ 2 (x +2) =20-(2×-5)
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Answer:
Given that 3x+2(x+2)=20-(2x-5)
3x + 2(x) + 2(2) = 20 – 2x -(-5)
3x + 2x + 4 = 20 – 2x + 5
3x + 2x + 2x = 20 – 4 + 5
7x = 21
x = 21/7
x= 3..
Checking:
3x + 2 (x+2)=20-(2x-5)
substitute x = 3
3(3) + 2(3+2) = 20 – (2(3) – 5)
9 + 2(5) = 20 -(6-5)
9 + 10 = 20 -(1)
19 = 19..
So x = 3
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