Question

Solve 3(2 –x ) = 6x
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Answer 1

Solution:-

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$\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$

$\implies$ Here in the question an equation is given, that is 3(2 - x) = 6x. Now the question has asked us to solve this equation and find the value of x. So, to solve this equation follow the steps given below.

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ANSWER:-

⪼ Value of x is 2/3.

GIVEN:-

⇢ Equation = 3(2 - x) = 6x

TO FIND:-

➡ Here we have to solve the equation and find the value of x.

SOLVING STEP BY STEP:-

• To solve this equation follow the steps below:-
• Take constant terms to R.H.S.
• Separate the constant terms from the variable.
• Take the separated term to R.H.S.
• Solve further.

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• Solving the equation:-

$\to \rm{3(2 - x) = 6x}$

$\to\sf {\underbrace{\underbrace{3(2} - x})} = 6x$

$\to \rm{6 - 3x = 6x}$

$\to \sf{Taking \: 3x \: to \: R.H.S.}$

$\to \rm{6 = 6x + 3x}$

$\to \rm{6 = 9x}$

$\to \rm{x = \dfrac{6}{9}}$

$\to \rm{x = \dfrac{ \not{6}}{ \not{9}} }$

$\underline {\boxed{ \sf \dag x = \dfrac{2}{3}}}$

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VERIFICATION:-

➤ L.H.S

$\to \sf{3\bigg( \dfrac{2}{1} - \dfrac{2}{3}\bigg)}$

$\to \sf{Taking \: L.C.M.}$

$\to \sf{3 \bigg(\dfrac{6 - 2}{3} \bigg)}$

$\to \sf{3 \times \dfrac{4}{3}}$

$\to \sf{ \dfrac{3}{1}\times \dfrac{4}{3}}$

$\to \sf{\dfrac{3 \times 4}{3}}$

$\to \sf{\dfrac{12}{3}}$

$\to \sf{\dfrac{ \not{12}}{ \not{3}} = 4}$

$\to \sf{4}$

➤ R.H.S

$\to \sf{6 \times \dfrac{2}{3}}$

$\to \sf{ \dfrac{6}{1} \times \dfrac{2}{3}}$

$\to \sf{ \dfrac{6 \times 2}{3}}$

$\to \sf{\dfrac{12}{3}}$

$\to \sf{\dfrac{ \not{12}}{ \not{3}}} = 4$

$\to \sf {4}$

$\therefore \sf {L.H.S = R.H.S}$

Hence, proved.

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