Question

solve 3(2u+v)=7uv
3u+3v=11uv

Answer 1

3(2u+v)=7uv => 6u+3v=7uv ----------------(1)
3u+3v=11uv  ---------------------(2)
from (1), 6u/uv + 3v/uv = 7uv/uv
6/v + 3/u = 7 ----------------------------------(3)
from (2), 3u/uv +3v/uv = 11uv/uv
3/v + 3/u = 11 ---------------------------------(4)
let 1/v=a and 1/u=b
therefore, 
                 6a+3b=7 -----------------------------(5)       (from equation 3)
and  
                3a+3b=11----------------------------(6)         (from equation 4)
subtracting equation 6 from 5
6a + 3b = 7
3a + 3b = 11
-    -          -                         ( changing of sign while subtracting )
3a = -4
a = -4/3
a = 1/v =-4/3
therefore, v=-3/4
putting a in the equation
3*-4/3 + 3b =11
-4 +3b = 11
3b=11+4 = 15
b=15/3=5/1
b=1/u=5/1
u=1/5
ans. v=-3/4 and u=1/5
HOPE IT HELPS !!!
 

Answer 2

In the 1st equation.....
3(2u+v)=7uv
6u+3v=7uv

In the 2nd equation....
3u+3v=11uv

Now subtract 2nd equation from 1st equation
6u+3v–(3u+3v)=7uv – 11uv
6u+3v–3u–3v= –4uv
3u= –4uv
canceling u from both sides
3= –4v
v=3/–4
v= –3/4

Putting the value of v in any of the equations

3u + 3(–3/4) =11u(–3/4)
3u – 9/4 = –33u/4
3u + 33u/4 = 9/4
taking LCM as 4
[12 u + 33u]/4 = 9/4

canceling 4 in denominator from both side
12u + 33u =9
45u=9
u=9/45
u=3/15=1/5

HOPE IT HELPS.... :-)