solve 3√2xsquare-5x-√2=0
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Answered by
3
3√2x^2-5x-√2=0
[3√2x^2-5x-√2=0]√2
6x^2-5√2x-2=0
By splitting middle term
6x^2-3√2x-2√2x-2=0
3√2x(√2x-1)-2(√2x-1)=0
(3√2x-2)(√2x-1)=0
x=2/3√2 , x=1/√2
Answered by
5
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3√2x²-5x-√2=0
USING SPLLITING THE MIDDLE TERM METHOD :
3√2x²-(6-1)x -√2 = 0
3√2x²- 6x + x-√2=0
3√2x(x-√2)+1(x-√2) = 0
(x-√2)(3√2x+1) = 0
SO,
x=√2 or x = -1/3√2✔
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