Math, asked by Megha412, 1 year ago

solve 3√2xsquare-5x-√2=0​

Answers

Answered by suwetha49
3

3√2x^2-5x-√2=0

[3√2x^2-5x-√2=0]√2

6x^2-5√2x-2=0

By splitting middle term

6x^2-3√2x-2√2x-2=0

3√2x(√2x-1)-2(√2x-1)=0

(3√2x-2)(√2x-1)=0

x=2/3√2 , x=1/√2

Answered by simran206
5

 <b >heya

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3√2x²-5x-√2=0

USING SPLLITING THE MIDDLE TERM METHOD :

3√2x²-(6-1)x -√2 = 0

3√2x²- 6x + x-√2=0

3√2x(x-√2)+1(x-√2) = 0

(x-√2)(3√2x+1) = 0

SO,

x=√2 or x = -1/3√2✔

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