Question

solve : 3 ³√40-4 ³√320- ³√5​

Answer 1

ANSWER:-

ln this ,first take the L.C.M of 40,320

l.c.m of 40=8×5

l.c.m of 320=8×8×5

now, substitute the products in the problem.

=3(3√40)-4(3√320)-(3√5)

=3[3√(8×5)]-4[3√(8×8×5)]-(3√5)

=3(2^3√5)-4(2.2^3√5)(-3√5)

=6.3√5-16.3√5-3√5

Now, take 3√5 as common

=3√5(6-16-1)

=3√5(-11)

=-3√5

Therefore,3√5 is the answer of your question.

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