Question

Solve 3/(3x-y) + 2/(3x+y) = 2, 10/(3x-y) + 2/(3x+y) = 11/2

Answer 1

$\textbf{Answer :}$

Given equations are

3/(3x - y) + 2/(3x + y) = 2 ...(i)

10/(3x - y) + 2/(3x + y) = 11/2 ...(ii)

On subtraction, we get

10/(3x - y) - 3/(3x - y) = 11/2 - 2

⇒ 7/(3x - y) = 7/2

⇒ 3x - y = 2 ...(iii)

Now, putting 3x - y = 2 in (i), we get

3/2 + 2/(3x + y) = 2

⇒ 2/(3x + y) = 2 - 3/2

⇒ 2/(3x + y) = 1/2

⇒ 3x + y = 4 ...(iv)

Now, adding (iii) and (iv), we get

6x = 2 + 4

⇒ 6x = 6

⇒ x = 1

Now, putting x = 1 in (iii), we get

3 (1) - y = 2

⇒ 3 - y = 2

⇒ y = 3 - 2

⇒ y = 1

∴ the required solution be

x = 1, y = 1

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Answer 2

Answer:

simple and easy answer for you