solve, 3+√6/√3+√2=a+b√3
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Answer:
value of a=0
value of b=1
Step-by-step explanation:
LHS:
3+ root 6(root 3-root 2)/3-2
3root 3-3root 2+roo 18 - root 12/1
3root 3-3root 2+3root 2-2root 3
3root 3-2root 3
root 3=a+b root3
a=0
b=1
THANK YOU......
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