Question

solve:3/(64)⅔+2/(16)¾+1/(129)⅓​

Answer 1

Answer:

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$\frac{3}{64 \times \frac{2}{3} } + \frac{2}{16 \times \frac{3}{4} } + \frac{1}{129 \times \frac{1}{3} }$

$= > \frac{3}{ \frac{128}{3} } + \frac{2}{ \frac{48}{4} } + \frac{1}{ \frac{129}{3} }$

$= > 3 \times \frac{3}{128} + 2 \times \frac{4}{48} + 1 \times \frac{3}{129}$

$= > \frac{3}{128} + \frac{8}{48} + \frac{3}{129}$

$= > \frac{3}{128} + \frac{1}{6} + \frac{1}{43}$

$= > \frac{387 + 2752 + 1152}{16512}$

$= > \frac{4291}{16512}$

Answer 2

64×

3

2

3

+

16×

4

3

2

+

129×

3

1

1

= > \frac{3}{ \frac{128}{3} } + \frac{2}{ \frac{48}{4} } + \frac{1}{ \frac{129}{3} }=>

3

128

3

+

4

48

2

+

3

129

1

= > 3 \times \frac{3}{128} + 2 \times \frac{4}{48} + 1 \times \frac{3}{129}=>3×

128

3

+2×

48

4

+1×

129

3

= > \frac{3}{128} + \frac{8}{48} + \frac{3}{129}=>

128

3

+

48

8

+

129

3

= > \frac{3}{128} + \frac{1}{6} + \frac{1}{43}=>

128

3

+

6

1

+

43

1

= > \frac{387 + 2752 + 1152}{16512}=>

16512

387+2752+1152

= > \frac{4291}{16512}=>

16512

4291