solve (3/7)+(-6/11)+(-8/11)+(5/11)
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3/7 + (- 6/11) + (- 8/21) + (5/22)
Taking L.C.M. of the denominators 7, 11, 21 and 22 and then solving it.
L.C.M. of 7, 11, 21 and 22 = 2*3*7*11
= 462
= (462/7)*3 - (462/11)*6 - (462/21)*8 + (462/22)*5
= (198/462) - (252/462) - (176/462) + (105/462)
= (303/462) - (428/462)
= (-125/462)
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