Question

Solve :(3ť 9t² + 27t) = 3t 1 ​

Answer 1

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): Dot was discarded near "t.^".

Step by step solution :

STEP

1

:

Equation at the end of step 1

((3 • (t3)) - 33t2) + 24t = 0

STEP

2

:

Equation at the end of step

2

:

(3t3 - 33t2) + 24t = 0

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

3t3 - 27t2 + 24t = 3t • (t2 - 9t + 8)

Trying to factor by splitting the middle term

4.2 Factoring t2 - 9t + 8

The first term is, t2 its coefficient is 1 .

The middle term is, -9t its coefficient is -9 .

The last term, "the constant", is +8

Step-1 : Multiply the coefficient of the first term by the constant 1 • 8 = 8

Step-2 : Find two factors of 8 whose sum equals the coefficient of the middle term, which is -9 .

-8 + -1 = -9 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and -1

t2 - 8t - 1t - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

t • (t-8)

Add up the last 2 terms, pulling out common factors :

1 • (t-8)

Step-5 : Add up the four terms of step 4 :

(t-1) • (t-8)

Which is the desired factorization