solve 3 and explain
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f(x) =x√2-1/x√2
in place of x use √2
√2 ×√2 -1/√2×√2
2-1/2
take LCM
=3/2
in place of x use √2
√2 ×√2 -1/√2×√2
2-1/2
take LCM
=3/2
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chikki9:
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given
f(x) = x√2 -1/x√2
f(x) = √2[x- 1/2x]
take f(√3+1/2) = √2{ (√3+1)/2 - 1/2 (√3+1)/2}
= √2{ (√3 +1)/2 - (√3 -1)/(√3+1)(√3-1)}
= √2 { (√3 +1)/2 -(√3-1)/2}
= √2{(√3+1-√3+1)/2}
=√2*2/2
=√2
f(x) = x√2 -1/x√2
f(x) = √2[x- 1/2x]
take f(√3+1/2) = √2{ (√3+1)/2 - 1/2 (√3+1)/2}
= √2{ (√3 +1)/2 - (√3 -1)/(√3+1)(√3-1)}
= √2 { (√3 +1)/2 -(√3-1)/2}
= √2{(√3+1-√3+1)/2}
=√2*2/2
=√2
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