Math, asked by IAMAlain22, 9 hours ago

Solve
3 cos2 300 – 4 sin^3 30° + 2sin^2 45°

Answers

Answered by Nishtha70
1

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Answered by sivapandukadavakollu
0

Answer:

sin 30 = 1/2

cos 45 = 1/root 2

tan 60 = root3

2 sin^2 30 - 3 cos^2 45 + tan ^2 60

= 2 ( 1/2 )^2 - 3 ( 1/root2 )^2 + ( root3 )^2

= 2 × 1/4 - 3 × 1/2 + 3

= 1/2 - 3/2 + 3

= - 2/2 + 3

= - 1 + 3

= 2

So 2sin^2 30 - 3cos^2 45 + tan^2 60 = 2

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