Math, asked by thivinkrishna2004, 5 months ago

Solve 3 cosAcosA = sinAsinA

Answers

Answered by harshitanaidu

0

Answer:

3cosx^2=sinx^2

3-3sinx^2=sinx^2

3/4=sinx^2

sinx= √3/2

x=60°

Step-by-step explanation:

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