Solve 3 number.
with solution
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i) 1 mole of C+o2-->CO2
so, 44grams of co2 is produced
ii)if 32g of o2 ---> 44g of co2
16g--->44*16/32= 22grams of CO2
iii) in this only 16 grams of oxygen is reacting that is only half of the o2 will react with 1/2 of Carbon .. so it will be half of 1st case
Therefore the ans will be 44/2=22grams
Note: in iii) case O2 is limiting reagent
so, 44grams of co2 is produced
ii)if 32g of o2 ---> 44g of co2
16g--->44*16/32= 22grams of CO2
iii) in this only 16 grams of oxygen is reacting that is only half of the o2 will react with 1/2 of Carbon .. so it will be half of 1st case
Therefore the ans will be 44/2=22grams
Note: in iii) case O2 is limiting reagent
PrincessManshi:
plz mark it as BRAINLIEST this had really helped u :)<3
But,, answer of 3rd one is comming 22g
are sure..? coz if 1 mole is giving 44g means ..2moles should give 88g na?
its just like if 1chocolate 5 rupees then 2 will be 10
I am not sure..i have seen a solution of NCERT on internet..so i have asked.. i am also confused.
okay.. i'll check it again... plz u too confirm it from your chem teacher and let me know too...
and don't get panic and this que for a long time.. move on to the next the que or go for sleep :-) <3
okk,,thanks☺☺
check it now.. did u understand?
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