solve 3 to the power x=5 to the power x-2
Answers
Answered by
169
Hello friend!
3^x = 5^(x-2)
Applying log on both the sides
log 3^x = log 5^(x-2)
【log n^a = a log n】
x log 3 = (x-2) log 5
x log 3 = x log 5 - 2log 5
2log 5 = x log 5 - x log 3
Taking x common
2 log 5 = x ( log 5-3)
2 log 5 / log 2 = x
【 x log n = log n ^ x】
log 5^2 / log 2 = x
log 25 / log 2 = x
Hope it helps!
3^x = 5^(x-2)
Applying log on both the sides
log 3^x = log 5^(x-2)
【log n^a = a log n】
x log 3 = (x-2) log 5
x log 3 = x log 5 - 2log 5
2log 5 = x log 5 - x log 3
Taking x common
2 log 5 = x ( log 5-3)
2 log 5 / log 2 = x
【 x log n = log n ^ x】
log 5^2 / log 2 = x
log 25 / log 2 = x
Hope it helps!
Answered by
65
Answer:
Step-by-step explanation:
3^x=5^x-2
Apply log on both sides
Iog3^x=log5^x-2
We know that loga^n = n log a
So,
X log 3= x-2 (log 5)
X log 3 =X (log 5) -2 (log 5)
X log 3 = X log 5 - 2 log 5
X log 3 - X log 5 = -2 log 5
-(X log 3 -X log 5) = 2 log 5
-X log 3 + X log 5 = 2 log 5
X(log 5-log 3) = 2log 5
Again,
Log a- log b=log a÷b
So,
X ( log 5/3)= 2 log 5
X (log 5/3)= log5^2
X (log 5/3) = log 25
X = log 25/log 5/3
That's it
Please mark as brainliest
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