Question

Solve 3^x+1 = 2^2-x.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\3^{x+1} = 2^{2-x} \\\\\ Solution:\\\\3^{x+1} = 2^{2-x}\\\\\ take \log \ on \ both \ side\\\\\rightarrow \log 3^{(x+1)} = \log 2^{(2-x)}\\\\\rightarrow (x+1) \log 3= (2-x)\log 2\\\\\rightarrow x\log 3 + \log 3= 2\log 2- x\log2\\\\\rightarrow x\log 3 +x\log2= 2\log 2- \log 3\\\\\rightarrow x(\log 3 +\log2)= 2\log 2- \log 3\\\\\rightarrow x= \frac{2\log 2- \log 3}{(\log 3 +\log2)}$

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