Question

Solve 3^x+1 = 2^2-x.​

Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ value: \\\\3^{x+1} = 2^{2-x}\\\\ \ Solution:\\\\3^{x+1} = 2^{2-x}\\\\\ take \ a\log \ in \ both \ side: \\\\\rightarrow \log3^{x+1} = \log2^{2-x}\\\\\rightarrow {(x+1)}\log3 = {(2-x)}\log2\\\\\rightarrow x\log3 +\log3 = 2\log2 -x\log2\\\\\rightarrow x\log3 + x\log2= 2\log2-\log3 \\\\\rightarrow x(\log3 + \log2)= 2\log2-\log3 \\\\\rightarrow x= \frac{2\log2-\log3}{(\log3 + \log2)}$

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