Math, asked by nilaskrishna, 11 months ago

Solve 3^(x+1)+3^(2x+1)=270

Answers

Answered by rajaksan45
24

Answer:

3^(x+1)+3^(2x+1)=270

3^(x+1)+3^(2x+1)=3^3×10

X+1+2x+1=30

3x=28

x=28/3

Answered by JeanaShupp
24

The value of x is 2.

Explanation:

The given equation : 3^{x+1}+3^{2x+1}=270

We can write 270 as 3\times3\times3\times2\times5=3^3\times10

By using exponent property : a^{m+n}=a^m\cdot a^n

The equation becomes 3^{x+1}+3^{x+1+x}=3^3\times10

\Rightarrow\ 3^{x+1}+3^{x+1}3^x=3^3\times(1+9)

Taking 3^{x+1} as common in LHS , we get

3^{x+1}(1+3^x)=3^3(1+3^2)\ \ \ [\because\ 3^2=9]

On Comparing both sides , we get

x+1=3\text{ and } x=2

That means x=2

Hence, the value of x is 2.

# Learn more :

If 3 power x= 270 then 3 power x-3=?

https://brainly.in/question/1624425

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