Solve 3/x-2 - 2/x-3 =4/x-3 - 3/x-1
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Step-by-step explanation:
LHS
= 3(x-3) - 2(x-2) / (x-2) (x-3)
= 3x-9-2x+4 / (x-2) (x-3)
= x-5 / (x-2) (x-3) -----------(1)
RHS
= 4(x-1) - 3(x-3) / (x-3) (x-1)
= 4x-4-3x+9 / (x-3) (x-1)
= x+5 / (x-3) (x-1) ------------(2)
Equating (1) & (2),
x-5 / (x-2) (x-3) = x+5 / (x-1) (x-3)
{x-3 gets cancelled}
x-5 / x-2 = x+5 / x-1
(x-5) (x-1) = (x+5) (x-2)
x^2-x-5x+5 = x^2-2x+5x-10
{x^2 gets cancelled}
-6x-3x = -10-5
-9x = -15
x = 15/9
x = 5/3
Hope it helps.....
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