Question

solve 3(x-2) - (2x + 1)=0
(a)3 (b) 7 (C) 5 (1) 6.​

Answer 1

Answer:

(3x2 -  2x) -  1  = 0

Factoring  3x2-2x-1  

The first term is,  3x2  its coefficient is  3 .

The middle term is,  -2x  its coefficient is  -2 .

The last term, "the constant", is  -1  

Step-1 : Multiply the coefficient of the first term by the constant   3 • -1 = -3  

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is   -2 .

     -3    +    1    =    -2    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -3  and  1  

                    3x2 - 3x + 1x - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   3x • (x-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (x-1)

Step-5 : Add up the four terms of step 4 :

                   (3x+1)  •  (x-1)

            Which is the desired factorization

Solve  :    x-1 = 0  

Add  1  to both sides of the equation :  

                     x = 1

thus , option d 1 is the correct answer

Step-by-step explanation:

Answer 2

Answer:

(b) 7

Step-by-step explanation:

3(x-2) - (2x + 1)=0

=> 3x - 6 - 2x - 1 = 0

=> x -7 = 0

=> x = 7