Question

solve 3/x-2/y=0and 2/x+5/y=19 Hence find a if y =ax+3

Answer 1

let us assume 1/x to be a and 1/y to be b

therefore the equations become,

3a - 2b = 0.........i

2a  + 5b = 19......ii


solving i and ii using elimination method,

we get ,  a=2

substituting a=2 in equation i

we get , b=3

therefore we got,

a=1/x=2 and b =1/y= 3

ie  x = 1/2 and y=1/3

now we know that,

y=ax+3

substituting the values of x and y,

we get,    -16/3


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