Question

Solve 3 X + 2y = 1 ; 2 x + 3 Y = 4 by elimination method​

Answer 1

${\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

1)

$\implies3x + 2y = 1 ...eq(1)$

2)

$\implies2x + 3y = 4 \: ...eq(2)$

${\large{\blue{\bold{\underline{Now,}}}}}$

▪︎ By Multiplying eq(1) by 2 and eq(2) by 3 we get,

$\implies2(3x + 2y = 1) \\ \\ \implies6x + 4y = 2 \: ....eq(3)$

And,

$\implies3(2x + 3y = 4) \\ \\ \implies6x + 9y = 12...eq(4)$

${\large{\blue{\bold{\underline{So,}}}}}$

▪︎ By subtracting eq(3) from eq(4) we get,

$\implies(6x + 9y) -(6x + 4y) = (12) - (2) \\ \\ \implies6x + 9y - 6x - 4y = 10 \\ \\ \implies9y - 4y = 10 \\ \\ \implies5y = 10 \\ \\ \implies \: y = \frac{10}{5} \\ \\ \implies \: y = 2.$

${\large{\blue{\bold{\underline{Therefore, }}}}}$

▪︎ By putting y =2 in eq(1) we get,

$\implies3x + 2(2) = 1 \\ \\ \implies3x + 4 = 1 \\ \\ \implies3x = 1 - 4 \\ \\ \implies3x = - 3 \\ \\ \implies \: x = \frac{ - 3}{3} \\ \\ \implies \: x = - 1$

☆ Therefore the required values of x and y are -1 and 2 respectively.