solve 3^(x+3) = 9^ (2x+1)
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3^(x+3) = 9^ (2x+1)
=>3^(x+3) =3^2(2x+1)
=>base is same then equate its degree
=>x+3=4x+2
=>4x-x=3-2
=>3x=1
Then x=1/3
=>3^(x+3) =3^2(2x+1)
=>base is same then equate its degree
=>x+3=4x+2
=>4x-x=3-2
=>3x=1
Then x=1/3
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