Question

solve 3(x+4)_2(2_x)=4(2x_1)+7​

Answer 1

Answer:

Given, 3(x+2)−2(x−1)=7

⇒3x+6−2x+2=7

⇒x+8=7

Subtract 8 on both sides,

x+8−8=7−8

⇒x=−1

Step-by-step explanation:

hope it will help you...☺️

Answer 2

$\huge {\boxed {\mathbb {QUESTION}}}$

solve

$3(x+4)-2(2-x)=4(2x-1)+7$

$\huge {\boxed {\mathbb {ANSWER}}}$

$3(x+4)-2(2-x)=4(2x-1)+7$

$\implies 3x+12-4+2x=8x-4+7$

$\implies 5x+8=8x+3$

$\implies 8x-5x=8-3$

$\implies 3x=5$

$\implies {\boxed {\boxed {x=\frac{5}{3}}}}$

$\huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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$\huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$IDENTITIES$

${(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$(a+b) (a-b)={a}^{2}-{b}^{2}$

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