Question

solve 3/x+8/y=-1, 1/x-2/y=2, where x, y are not equal to zero​

Answer 1

Answer:

Let 1 - X and 1/y = u = v

then the equation becomes,

3u8v = 1 → (1)

and, u-2v = 2 → (2)

solving (1) and (2) we get,

u=1 and v = 1 /2

'.' X = 1/u = 1

and y = 1/v = -2

Answer 2

Answer:

$.$

Step-by-step explanation:

The given equations are

`3/x + 8/y = - 1` ...(1)

`1/x - 2/y = 2` ...(2)

Let `1/x = u and 1/y = v`

(1) and (2) will become

3u + 8v = -1 ...(3)

u - 2v = 2 ...(4)

Multiply (4) with 4

4u - 8v = 8 ...(5)

Adding (3) and (5) we get

7u = 7

⇒ u = 1

Putting this value in (4)

1 - 2v = 2

⇒ v = `(-1)/2`

Now

`1/x = u`

⇒ `1/x = 1`

⇒ x = 1

And

`1/y = v`

⇒ `1/y = (-1)/2`

⇒ y = - 2