solve (-3-y)² using Identity
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by using identity (a-b)²
(-3- y)²
-3² +(-y²) -2(-3)(-y)
9 - y² -6y
or -y² -6y + 9
by factorising
-y² -3y -3y +9
y[y-3] +3[y-3]
(y+3) (y-3)
- 1st we use identity of a-b² to get an equation
- then we factorise it by using mid term splliting
- so we get two value of y either -3 or +3
- we can slove this by quadratic formula
- after unsing identity
hope it helps you
be brainly
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