Question

solve........................

Answer 1

✴hy✴
here is your answer

1. replacing a by 2x and b by 3y in the identity

(a+b)³=a³+b³+3ab (a+b), we have

➡ (2x+3y)³=(2x) ³+(3y) ³+3×2x×3y×(2x+3y)

➡ (2x+3y)³=8x³+27y³+18xy×2x+18xy×3y

➡ (2x+3y)³=8x³+27y³+18xy×2x+18xy×3y

➡ (2x+3y)³=8x³+27y³+36x²y+54xy²

2. replacing a by 3x and b by in the same identity

➡(3x-2y) ³=(3x)³-(2y) -3×3x×2y×(3x-2y)

➡(3x-2y) ³=27x³-8y³-18xy×(3x-2y)

➡(3x-2y) ³=27x³-8y³-54x²y+36xy²

I hope you understand