Math, asked by Rohit5555555, 5 months ago

solve..............................​

Attachments:

Answers

Answered by shazeekhan47
0

Answer:

Cant help (sorry) ........•••••••

Answered by vipashyana1
0

Answer:

1)g(x)=0—›x-1=0—›x=1

p(x)=0

—›2x²+kx+√2=0

—›2(1)²+k(1)+√2=0

—›2+k+√2=0

—›k+2+√2=0

—›k=(-2)-√2

2)2x²+7x+3

=2x²+6x+x+3

=(2x²+6x)+(x+3)

=2x(x+3)+1(x+3)

=(x+3)(2x+1)

4)(2x-y+z)²

Using the identity:-

(a-b+c)²=a²+b²+c²-2ab- 2bc+2ca

a=2x, b=y, c=z

=(2x)²+(y)²+(z)²-2(2x)(y)-2(y)(z)+2(z)(2x)

=4x²+y²+z²-4xy-2yz+4zx

5)(2a-3b)³

Using the identity:-(a-b)³=a³-b³-3ab(a-b)

a=2a, b=3b

=(2a)³-(3b)³-3(2a)(3b){2a-3b}

=8a³-27b³-18ab{2a-3b}

=8a³-27b³-36a²b+54ab²

6)64m³-343n³

(4m)³-(7n)³

Similar questions