solve 31x+29 y=33 , 29x+31y=27
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The given equations are
31x + 29y = 33 ..... (1)
29x + 31y = 27 ..... (2)
Using substitution method.
From (1), we get
y = (33 - 31x)/29
Substituting y = (33 - 31x)/29 in (2), we get
29x + 31 (33 - 31x)/29 = 27
or, (29 * 29 - 31 * 31) x + 31 * 33 = 27 * 29
or, (31² - 29²) x = 33 * 31 - 29 * 27
or, 120x = 240
or, x = 2
Then y = (33 - 31 * 2)/29 = - 1
Therefore the required solution is
x = 2, y = - 1
Another method.
Adding (1) and (2), we get
x + y = 1
or, y = 1 - x
From (1), we get
31x + 29 (1 - x) = 33
or, 31x + 29 - 29x = 33
or, 2x = 4
or, x = 2
Then y = 1 - 2 = - 1
Therefore the required solution is
x = 2, y = - 1
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